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(IIT JEE 2000)
1) sp, sp3 and sp2 respectively
2) sp, sp2 and sp3 respectively
3) sp2, sp and sp3 respectively
4) sp2, sp3 and sp respectively
Logic:
Hybridization in central atom can be determined in the following steps:
i) Write the Lewis structure to get a rough idea about the structure of molecule.
ii) Finding the number of σ-bonds:
The number of σ-bonds = number of atoms with which the central atom is directly linked to.
Note: Only we need to find the number of σ-bonds. If there is a double or triple bond, remember that it constitutes only one σ-bonds.
iii) Finding the number of lone pairs on central atom:
The number of lone pairs = (v-b-c) / 2
v = no. of valence electrons in central atom.
b = no. of bonds (including both σ & π bonds) formed by central atom.
c = charge on the molecule or ionic species.
Solution:
In halogensinity of
Conclusion:
We can con.
(AIEEE - 2004)
a) oxygen is more
Solution:
When an electr result, se.
Conclusion:
The correct option is
1)
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Author: Aditya vardhan Vutturi