(AIEEE 2010)
a) 325 nm
b) 743 nm
c) 518 nm
d) 1035 nm
Logic:
Since energy is conserved, the energy, Eabs of absorbed photon is equal to total of energies, (E1+ E2) of two photons emitted.
i.e. Eabs = E1+ E2
Where:
E1 = Energy of first photon emitted
E2 = Energy of second photon emitted
Energy, E and wavelength, λ of a photon are related as follows:
E = hc/λ
Where:
h = Planck's constant
c = velocity of light (a constant)
Therefore:
1/λabs = 1/λ1 + 1/λ2
Solution:
Upon substituting the known values in above equation:
1/355 = 1/680 + 1/λ2
By solving above equation:
λ2 = 742.76 nm
Conclusion:
Correct option is "b".
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a) 662
b) 1324
c) 66.2
d) 6.62
Solution:
We know that:
E = hc/λ
or
λ= hc/E
Therefore:
wavelength λ = hc/E = 6.626 x 10-27 erg s x 3.0 x 1010 cm s-1 / 3 x 10-12 erg = 6.626 x 10-5 cm
Now:
1 cm = 107 nm
Therefore the wavelength in nm = 6.626 x 10-5 x 107 nm = 6.626 x 102 nm = 662.
a) 1/4
b) 4
c) 1/2
d) 2
Solution:
From
E = hc/λ
The ratio of energies of two radiations is given by:
E1/E2 = λ2/λ1 = 4000/2000 = 2
Note: Energy is inversely proportional to wavelength.
a) 5.0 x 1014
b) 2.0 x 1013
c) 5.0 x 1016
d) 2.0 x 1014
Solution:
c = νλ
where
ν = frequency
λ = wavelength
c = velocity of light
Therefore:
ν = c / λ = 3.0 x 108 m s-1 / 600 x 10-9 m = 5.0 x 1014 s-1 = 5.0 x 1014 Hz
1) If the wavelength of an electromagnetic radiation is 2000 Å , what is the energy in ergs?
2) What is the wavenumber of electromagnetic radiation that has a wavelength 3 x 10-8 cm?
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